tipo axim.
10!*9!/6!*14!=
10*9*8*7*6!*9!/6!*14*13*12*11*10*9!=corta 9! c/ 9! e 6!c/ 6!
simplifica 10 c/ 10 9c/12 7c/ 14
3*8/2*13*4*11=24/70=simplifica2
12/35
2006-10-26 08:42:28
·
answer #1
·
answered by Capitão Caverna & Camila 4
·
0⤊
1⤋
10!*9!/6!(19-5)!=
9.8.7
---------=
14.13.12.11
==>
3/143
<><>
2006-10-26 17:21:53
·
answer #2
·
answered by aeiou 7
·
0⤊
0⤋
10!*9! / 6! (19-5)! =
10! * (9*8*7*6)! / 6!*(14*13*12*11*10)!
simplificando teremos:
(9*8*7)/(14*13*12*11)=
504/24024=
simplificando por 168 teremos:
3/143
2006-10-26 15:51:13
·
answer #3
·
answered by chsoareslopes 5
·
0⤊
0⤋
Bom lá vai:
10! x 9! ...... 10! x 9!
---------------- = ----------------
6! x (19-5)! ..... 14! x 6!
10! x 9x8x7x6!
----------------------------
14x13x12x11x10! x 6! Nesse caso, pela propriedade elimina-se o 10! e 6! de ambos, logo:
9 x 8 x 7
--------------------
14x13x12x11
504
---------- = simplificando por 168
24024
fica:
3
----
143
muita paz, um abraço.
Desculpa o mau jeito, mas é difícil fazer essas coisas aqui.
2006-10-26 15:49:43
·
answer #4
·
answered by Anonymous
·
1⤊
1⤋
10!*9!/6!(19-5)!= 2 (pontos)
2006-10-27 09:49:23
·
answer #5
·
answered by Nivel 3 3
·
0⤊
1⤋
Estude.
2006-10-26 17:58:38
·
answer #6
·
answered by flor-de-lys 6
·
0⤊
1⤋
10!*9! / 6!(19-5)!
10!*9! / 6!*14!
Pode se substituir:
9! com 9*8*7*6!
e
14! com 14*13*12*11*10!
Assim fica:
(10! * 9 * 8 * 7 * 6!) / (6! * 14 * 13 * 12 * 11 * 10!)
Ai pode simplificar 10! e 6! dos dois lados e vai ficar:
(9 * 8 * 7) / (14 * 13 * 12 * 11)
Substitui:
9 com 3 * 3
8 com 4 * 2
14 com 7 * 2
12 com 4 * 3
(3 * 3 * 4 * 2 * 7) / (7 * 2 * 13 * 4 * 3 * 11)
Simplificamos 2, 3, 4 e 7 dos dois lados e vamos ter:
(3) / (13 * 11)
Resulta:
3 / 143 = 0,020979021
2006-10-26 17:29:55
·
answer #7
·
answered by Andrea F 3
·
0⤊
1⤋
10!*9!/[6!(19-5)!]
10!*9!/(6!*14!)
10!*9*8*7*6!/(6!*14*13*12*11*10!)
(9*8*7)/(14*13*12*11) = 3/(11*13) = 3/143
2006-10-26 15:42:40
·
answer #8
·
answered by Luiz S 7
·
0⤊
1⤋
Mando no excel!!
2006-10-26 15:32:27
·
answer #9
·
answered by JÔ (Rosa Azul) 5
·
0⤊
1⤋
joga no excel.
2006-10-26 15:30:24
·
answer #10
·
answered by Ricardo 2
·
0⤊
1⤋