(2x+1)²=4 . (x+2)²
(2x+1) . (2x+1) = 4 . [(x+2) . (x+2)]
4x² + 2x + 2x + 1² = 4 . [x² + 2x + 2x + 2²]
4x² + 4x + 1 = 4 . [x² + 4x + 4]
4x² + 4x + 1 = 4x² + 16x + 16
4x - 16x = 16 - 1
- 12x = 15
x = - 15 / 12 = - 5 / 4
2006-10-21 13:51:15
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answer #1
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answered by will 5
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(2x+1)²=4(x+2)²
4x² + 4x + 1 = 4x² + 16x + 16
corta o 4x²
4x + 1 = 16x + 16
x pra um lado, sem x para o outro
-12 x = 15
x = -15/12
x = -5/4 = 1,25
2006-10-21 15:20:06
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answer #2
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answered by z0mb0com 2
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4x²+4x+1=4(x²+4x+4)
4x²+4x+1=4x²+16x+16
4x²-4x²+4x-16x=16-1
-12x=15
12x=-15
x=-15/12 ou x=-1,25
2006-10-21 13:59:17
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answer #3
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answered by Efeoitomeia 4
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Vamos lá bem explicadinho:
( 2x + 1 )² = 4 ( x + 2 )²
4x² + 4x + 1 = 4 ( x² + 4x + 4 )
4x² + 4x + 1 = 4x² +16x + 16
4x² + 4x + 1 - 4x² -16x -16 = 0
-12x - 15 = 0
12x = -15
x = - 15 / 12
x = - 5 / 4
Valeu!
2006-10-21 13:58:26
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answer #4
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answered by Josenildo S 6
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4X^2 + 4x +1 = 4X^2 + 16x + 16
4X + 1 = 16X + 16
12X = -15
X = -5/4
2006-10-21 13:56:48
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answer #5
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answered by Anonymous
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ESSA AKI ESTÁ BEM EXPLICADINHA!!!
resolvendo
(2X+1).(2X+1)=4[(X+2).(X+2)]
4x☻+2x+2x+1=4[(x+2).(x+2)
4x☻4x+1=4[x☻+4x+4] (☻=2 é o quadrado nao sei colok)
4x☻+4x+1=4x☻+16x+16 (o "x" passa para o primeiro mudando o sinal e o numero tmb mudando o sinal)
4x☻-4x☻+4x-16x=16-1
4x-16x=16-1
-12x=15 (-1) o primeiro terno jamais poderá ficar negativo por isso multiplica por (-1)
12x=-15
x=-15/12
x=-5/3
2006-10-21 17:43:22
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answer #6
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answered by curioso 2
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(2x+ 1)² = 4(x+ 2)²
4x²+ 4x+ 1 = 4x²+ 16x+ 16
12x = -15
x = -5/4
2006-10-21 13:56:01
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answer #7
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answered by Illusional Self 6
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(2x+1).(2x+1)=4(x+2).(x+2)=
4x²+2x+2x=1=4+x²+2x+2x+4
4x²+2x+2x-x²-2x-2x=4+4
5x²+4x-4x=+8
5x²=8
x²=8/5
sei lah c eh assim
2006-10-21 14:01:35
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answer #8
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answered by MeanGirls 1
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