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已知m的八次方=81,則6個m的連乘積為多少 ?
(煩請將計算過程列出,謝謝)

2006-10-16 03:56:20 · 1 個解答 · 發問者 大白 1 in 教育與參考 考試

1 個解答

m8 = 81,m6 = ?m8 = 81 → m4 = 9 → m2 = 3m8 / m2 = m6 = 81 / 3 = 27<<所以 m6 = 27>>

2006-10-16 08:18:43 補充:
1.相乘時指數相加,相除時指數相減。例如:m^2 * m^2 = m^(2+2) = m^4m^8 / m^2 = m^(8-2) = m^6 (^代表次方)2.m^8 = 81 → m^4 *m^4 = 81 = 9*9 → m^4 = 9m^4 = 9 → m^2*m^2 = 3*3 → m^2 = 3

2006-10-16 04:13:13 · answer #1 · answered by ~~初學者六級~~ 7 · 0 0

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