若f(x)=x 2 -2x+3,試求
(1)lim f(x)-f(2)/x-2 ( 2)lim f(2+h)-f(2)/h
x→ 2 h→ 0
2006-10-15 16:06:59 · 1 個解答 · 發問者 嬿 1 in 教育與參考 ➔ 考試
(1) f(x) - f(2) lim ─────x→2 x - 2 x² - 2x + 3 - (2² - 2(2) + 3)= lim ─────────── x→2 x - 2 x² - 2x + 3 - 3= lim ────── x→2 x - 2 x² - 2x= lim ──── x→2 x - 2 x(x - 2)= lim ──── x→2 x - 2 = lim x x→2= 2(2) f(2 + h) - f(2) lim ──────h→0 h (2 + h)² - 2(2 + h) + 3 - (2² - 2(2) + 3)= lim ──────────────── h→0 h 4 + 4h + h² - 4 - 2h= lim ──────── h→0 h 2h + h²= lim ──── h→0 h h(2 + h)= lim ──── h→0 h= lim (2 + h) h→0= 2
2006-10-15 21:28:59 補充:
以上其實都是f'(2)f'(x) = 2x - 2f'(2) = 2(2) - 2 = 2
2006-10-15 17:23:07 · answer #1 · answered by chan 5 · 0⤊ 0⤋