Colocando sinais ou equações, mostre que é correto afirma:
0 0 0 = 6
1 1 1 = 6
2 + 2 + 2 = 6 Exemplo
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
2006-09-24 10:39:43 · 8 respostas · perguntado por Hélder S 2 em Ciências e Matemática ➔ Matemática
(0!+0!+0!)! = (1+1+1)! = 3! = 6
(1+1+1)!= 3!= 6
2+2+2 = 6
3 x 3 - 3= 6
(4+4)-raiz quadrada de 4= 8-2 = 6
5 / 5+ 5= 1 +5 = 6
6-6+6= 6
7-7 / 7 = 7 - 1 = 6
raiz cubica de 8 + raiz cubica de 8 + raiz cubica de 8 = 2+2+2= 6
9 / raiz quadrada de 9 + raiz quadrada de 9 = 9 / 3 +3 = 3 +3 = 6
Dez pontos
2006-09-24 11:14:50 · answer #1 · answered by sombra 7 · 0⤊ 0⤋
Ola;
Interessante exercicio:
(0!+0!+0!)! = (1+1+1)! = 3! = 6
(1+1+1)!= 3!= 6
2+2+2 = 6
3 x 3 - 3= 6
(4+4)-(4)^1/2= 8-2 = 6
5 / 5+ 5= 1 +5 = 6
6-6+6= 6
7-7 / 7 = 7 - 1 = 6
(8)^1/3 + (8)^1/3 + (8)^1/3 = 2+2+2= 6
9 / (9)^1/2 + (9)^1/2 = 9 / 3 +3 = 3 +3 = 6
Abraço
2006-09-24 12:23:15 · answer #2 · answered by alvenez 4 · 0⤊ 0⤋
0 0 0-Impossivel
(1+1+1)!
2+2+2
3x3-3__
4+4-V4 (4+4-raiz de 4)
5+5/5
6+6-6
7-7/7
8 8 8 -Impossivel Não vale raiz cubica pois tem de escrever o 3! Raiz quadrada é OK!
V9x9 -V9 (raiz de 9x9 - raiz de 9)
2006-09-24 11:12:11 · answer #3 · answered by Frajola 4 · 0⤊ 0⤋
3*3(9)-3=6
6+6(12)-6=6
só consegui essas, depois fala a respota ae.
2006-09-24 11:07:00 · answer #4 · answered by andre_fodα 5 · 0⤊ 0⤋
8+8+8=16+8=24 =2+4=6;
-6+6+6=0+6=6...
2006-09-24 10:52:39 · answer #5 · answered by Leninha 6 · 0⤊ 0⤋
(6+6)-6=6
2006-09-24 10:48:07 · answer #6 · answered by "Consciencia" 3 · 0⤊ 0⤋
(3x3)-3 = 6
6+6-6 = 6
2006-09-24 10:43:46 · answer #7 · answered by decio 4 · 0⤊ 0⤋
Eu só quero 1+1=2
2006-09-24 10:42:29 · answer #8 · answered by briam 3 · 0⤊ 1⤋