我想要問的歌名是:似曾相識 ─ Somewhere in Time
但是我不知道是誰唱的,是一首英文老歌,不知道哪裡可以聽到這首歌,或是有這首歌的人可以寄給我嗎?
感激不盡唷!^^
2006-09-24 00:32:23 · 2 個解答 · 發問者 Melody 2 in 娛樂與音樂 ➔ 音樂 ➔ 其他:音樂
謝謝你的幫忙,但是我要找的歌不是這首內,不好意思唷!很感謝你^^
2006-09-24 20:27:28 · update #1
Somewhere in time(似曾相識)Somewhere in timeThis story starts to writeJoining two hearts that beat as oneTo love and shardAs time goes by living in fantasiesWhere roses rain on usWherever we hideTears in my eyesWe're running out of timeSplitting two hearts that bleedWith burning love and careStumble and fallCatch me with your armsJust hold me close to youAnd wipe out my tearsPromise to tryTo hold on tightOur dreams are made insideThis love to keep us aliveCherish tonightWell stay togetherSomewhere in timeWe shall believeTrue love is hard to findRub on this magic lanternMake a special wish then close your eyesLet memories fade awayKnowing well stand the test of timeTo keep us alive我找不到是誰唱的不過他好像有收錄在"1995葛萊美喝采"
2006-09-30 12:38:26 · answer #1 · answered by ? 6 · 0⤊ 0⤋
Somewhere in time TracySomewhere in timeYou came into my worldLove was beyond what I imagined love would beNow just a dreamI hold till the end of timeHoping someday we'll find what we left behindThere'll come a dayOur paths will meet againWe'll cross the bridge of time and space to a love that's freeNo more goodbyeNo lonely waitingThat'll be our day to love, to live all our dreams☆If we believe and keep aliveThe hope that love will stand the test of distance and timeThen we shall find our new tomorrowSomewhere in timeSomeday there'll be no time between usThere'll just be endless days for us to love and shareWe'll rise above the tears of our lonely yearsInto a world beyond todayIn another somewhere(☆)曾幾何時 黃鶯鶯曾幾何時你來到我的世界裡愛情遠比我想像的美麗但是現在,這只是個夢直到最後一刻我仍緊緊的握住希望有一天,我們能找回之前所留下的一切會有那麼一天我們將會再重新交會一同穿越時空的橋,得到無止盡的愛不用說再見也不用再等待那天將是我們相愛的日子,一同實現夢境的日子如果彼此深信,並且認真的生活著 愛情就算會面臨距離與時間的考驗但是在某時某刻我們將會發現嶄新的明天有一天我們之間將不再擁有任何時間相處那就是我們一同分享與相愛的末日我們將會克服這些痛苦的歲月直到來生又在於某處相遇http://www.tienma.com/html2/13033.htm
2006-09-24 01:49:21 · answer #2 · answered by Indigo Children 7 · 0⤊ 0⤋