2006-09-22 06:13:12 · 21 respostas · perguntado por Daniel 1 em Ciências e Matemática ➔ Matemática
999 + 9/9
2006-09-22 06:20:32 · answer #1 · answered by Anonymous · 3⤊ 0⤋
999,99999999999999999999999999999999...
por que matematicamente 0,99999... é 1
2006-09-22 13:16:58 · answer #2 · answered by ¬,¬ 4 · 4⤊ 0⤋
999999/999,999= 1000 exato.
2006-09-22 13:29:57 · answer #3 · answered by Gustavo S 4 · 2⤊ 0⤋
(9999-999)/9
2006-09-22 17:52:59 · answer #4 · answered by ammessias 1 · 1⤊ 0⤋
999,999999999.....
sedo este número uma dízima periódica de 9
poderiamos representá-lo como:
999+0,9+0,09+0,009+...+0,00......09
O último termo seria tão ínfimo que se tenderia a 0
logo podemos representar como:
999+0,9+0,09+0,009+...+0
o que seria a soma da progrecao aritmética tendendo a zero:
999+ S
S=0,9+0,09+0,009+...+0
0,1S=0,09+0,009+....+0
Substituindo 0,1S na fómula de cima:
S=0,9 + 0,1S
S-0,1S=0,9
0,9S=0,9
S=1
então
999 + S => 999 + 1 = 1000
2006-09-22 13:25:08 · answer #5 · answered by raphael z 2 · 1⤊ 0⤋
Que tal
999 + 9/9???
2006-09-23 17:23:49 · answer #6 · answered by Xiquim 7 · 0⤊ 0⤋
999 + 9/9 =)
2006-09-22 17:36:19 · answer #7 · answered by ? 2 · 0⤊ 0⤋
999,99999999999999999~1000
2006-09-22 15:09:02 · answer #8 · answered by Taz 2 · 0⤊ 0⤋
Pode ser 999 + (9 / 9)
Ou então 9999 / 9,999
2006-09-22 13:46:20 · answer #9 · answered by hkotsubo 2 · 0⤊ 0⤋
seria assim: 999+(9/9). ok?
2006-09-22 13:23:47 · answer #10 · answered by [-KTS-] 1 · 0⤊ 0⤋