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1) 1 1 1 = 6
2) 2 2 2 = 6
3) 3 3 3 = 6
4) 4 4 4 = 6
5) 5 5 5 = 6
6) 6 6 6 = 6
7) 7 7 7 = 7
8) 8 8 8 = 8
9) 9 9 9 = 9

2006-08-25 08:02:23 · 7 respostas · perguntado por J L A 2 em Ciências e Matemática Matemática

desculpem, cometi um erro a partir do setimo. Agora está correto. Vamos tentar?
1) 1 1 1 = 6
2) 2 2 2 = 6
3) 3 3 3 = 6
4) 4 4 4 = 6
5) 5 5 5 = 6
6) 6 6 6 = 6
7) 7 7 7 = 6
8) 8 8 8 = 6
9) 9 9 9 = 6

2006-08-25 09:08:59 · update #1

7 respostas

1) (1+1+1)! = 6
2) 2+2+2 = 6
3) 3+(3*3)^(1/2) = 6 (entenda o "^1/2" como raiz quadrada, ok?)
4) 4+(4+4)^(1/3) = 6 ("^1/3" significa raiz cúbica).
5) 5+(5/5) = 6
6) 6+6-6 = 6 (também pode ser (6*6*6)^(1/3) = 6)
7) 7-(7/7) = 6
8) (8^1/3)+(8^1/3)+(8^1/3) = 2+2+2 = 6 (entenda "^1/3" como raiz cúbica)
9) (9+9)/(9^1/2) = 18/3 = 6 ("^1/2" significa raiz quadrada)

2006-08-25 08:18:56 · answer #1 · answered by Verbena 6 · 0 0

(1+1+1)! = 6
2+2+2 = 6
(3x3)-3= 6
4! /4 x 4º = 6
(5/5)+5= 6
7+7-7= 7
8+8-8= 8
9+9-9= 9

Não sei se era isso que v. queria, mas os resultados dão certo =oP

2006-08-25 15:17:34 · answer #2 · answered by ¬,¬ 4 · 1 0

1) 1.1+1 = 6
2) 2+2+2 = 6
3) 3.3 -3 = 6
4) 444 = 6
5) 5:5+5 = 6
6) 6:6x6 = 6
7) 7:7x7 = 7
8) 8x8:8 = 8
9) 9x9:9 = 9

2006-08-25 16:20:37 · answer #3 · answered by aeiou 7 · 0 0

(0!+0!+0!)!=6

(1+1+1)!=6

2+2+2=6

3*3-3=6

(4^1/2 + 4^1/2 +4^1/2)=6

5/5 +5=6

6-6+6=6

7-7+7=7

8-8+8=8

9-9+9=9

2006-08-25 15:24:21 · answer #4 · answered by zero 2 · 0 0

1) (1+1+1)! = 6
2) 2+2+2 = 6
3) 3*3-3 = 6
4) (4!/4)x 4º = 6
5) (5/5)+5 = 6
6) 6-6+6 = 6
7) 7-7+7 = 7
8) 8-8+8 = 8
9) 9-9+9 = 9

2006-08-25 15:19:45 · answer #5 · answered by Junior 2 · 0 0

1)
2)+e+
3)
4)raiz em todos os quatros e os sinais +e+
5)
6)+e-
7)+e-
8)+e-
9)+e-
Desculpe, só consegui fazer essses.

2006-08-25 15:14:34 · answer #6 · answered by Ark 4 · 0 0

a 1 nao se uasa nenhuma a
2) 2+2+2=6
3)3*3-3=6
e o resto vah descobrir q q eu te de a resposta neh

2006-08-25 15:10:45 · answer #7 · answered by yago b 2 · 0 1

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