若ln(x平方+y平方)+2arctan(x/y)=0,dy/dx=?
Ans: x+y/x-y
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2006-07-10 12:24:14 · 1 個解答 · 發問者 JEFF 1 in 教育與參考 ➔ 考試
ln(x²+y²)+2tan-1(x/y) = 0隱微分法(1/(x²+y²))(2x+2ydy/dx)+2(1/(1+(x/y)²)(y-xdy/dx)/y²=0剩下只是化簡(x+ydy/dx)/(x²+y²)+(y²/(x²+y²))(y-xdy/dx)/y²=0(x+ydy/dx)/(x²+y²)+(y-xdy/dx)/(x²+y²)=0x+ydy/dx+y-xdy/dx=0x+y-(x-y)dy/dx=0dy/dx=(x+y)/(x-y) 註: d(xn)/dx=nxn-1 d(lnx)/dx=1/x d(tan-1x)/dx=1/(1+x²) d(f(x)/g(x))/dx=(g(x)(df(x)/dx)-f(x)(dg(x)/dx))/(g(x))² dy/dx=(dy/du)(du/dx)
2006-07-10 21:00:43 · answer #1 · answered by chan 5 · 0⤊ 0⤋