KAlSi3O8+H2O+CO2→K+ +HCO3- + H4SiO4+ KAl3Si3O10(OH)2
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2006-03-19 19:42:50 · 2 個解答 · 發問者 紫忱. 1 in 科學 ➔ 化學
依序為 3 14 2 2 2 6 1
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2006-03-20 09:38:01 · answer #1 · answered by 成哥 1 · 0⤊ 0⤋
3[KAlSi3O80] +14[H2O] + 2[CO2] →2[(K+)+(HCO3-)] + 6[H4SiO4] + [KAl3Si3O10(OH)2]因右邊[KAl3Si3O10(OH)2]中Al有3個故左邊[KAlSi3O80]應為3的倍數設其為3及[KAl3Si3O10(OH)2]為1則[(K+)+(HCO3-)] 應為2[CO2]亦應為2[H4SiO4]應為6[H2O]應為14
2006-03-20 12:00:00 · answer #2 · answered by fumi 6 · 0⤊ 0⤋