What is the empirical formula of a compound that contains 43.6% P and 56.4% O?
2005-11-17 02:15:47 · 2 個解答 · 發問者 Frank 7 in 科學 ➔ 化學
好像不對吧!!
2005-11-18 17:13:26 · update #1
原子故數比=莫耳數比(=質量/原子量)
P : O
=43.6/31:56.4/16
=1.406 : 3.525.........(同除以1.406)
=1 : 2.5
=2:5
empirical formula----- P2O5
2005-11-20 11:52:31 · answer #1 · answered by linichi.tw 6 · 0⤊ 0⤋
P : .436/.564 = .773
O: .564/.564 = 1
當 P 和 O 都乘4時
P : .773*4 = 3.09
O : 1*4 = 4
所以是 P3 O4
2005-11-17 03:24:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋