1)X^2-Y^2+4x-2y+3
2) 2x^2-5xy-3y^2+x+11y-6
3)2x^2-7xy+3y^2+5xz-5yz+2z^2
4.因式分解xy-3x-y^2+2y+3
5.若xy-3x-y^2+2y+3=1，且x、y均為整數，求數對(x,y)=?
2005-11-12 19:10:19 · 2 個解答 · 發問者 ? 1 in 教育與參考 ➔ 考試
1.x^2-y^2+4x-2y+3=(x+2)^2-(y+1)^2
2.2x^2-5xy-3y^2+x+11y-6=(2x+y-3)(x-3y+2)
3.2x^2-7xy+3y^2+5xz-5yz+2z^2=(2x-y+z)(x-3y+2z)
4.xy-3x-y^2+2y+3=(x-y-1)(y-3)
5.(x,y)=(6,4)
2005-11-12 20:35:46 · answer #1 · answered by Anonymous · 0⤊ 0⤋
第一題和第五題的答案好像錯了哦!
2005-11-14 10:12:50 · answer #2 · answered by Frank 7 · 0⤊ 0⤋