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1+2-3+4-5+6-7+8-9+10-11+12-13+14-158+16-17+18-19+20-21+22-23+24-25+....................加減到100等於多少

2005-10-11 17:08:41 · 6 個解答 · 發問者 任坊 1 in 遊戲與休閒活動 其他:遊戲與休閒活動

6 個解答

1+2-3+4-5+6-7+8-9+10.....-99+100
=1+(2-3)+(4-5)+(6-7)+(8-9)+(10..-99)+100
=1+49個(-1)+100
=52

2005-10-11 17:11:43 · answer #1 · answered by 愷威 2 · 0 0

2-3=-1,4-5=-1,6-7=-1,以此類推,均為-1
從2到99共有49組[---(99-2)+1]/2=49
也就是49個-1,等於-49
接著再1+100-49=52
答案就出來了~>.<~

2005-10-11 17:51:29 · answer #2 · answered by ? 2 · 0 0

98/2=49x-1=-49
-49+1=-48
-48+100=52

Answer:
2-3=-1,4-5=-1,6-7=-1...以此類推偶數減基數等於-1的共有49組
再加上100個數字中(2-3+4-5+6...-99),剩餘的兩個數字1和100就是答案啦!

2005-10-11 17:38:03 · answer #3 · answered by ? 3 · 0 0

1+2-3+4-5+6-7+8-9+10-11+12-13+14-158+16-17+18-19+20-21+22-23+24-....
可以變成
1+(2-3)+(4-5)+(6-7)+...+(96-97)+(98-99)+100=1+100再減49個1=101-49=52

2005-10-11 17:14:27 · answer #4 · answered by ? 4 · 0 0

 1+2-3+4-5+6-7+8-9+10-..-99+100=1 +(2-3)+(4-5)+(6-7)+(8-9)+....+(98-99)+100=101 -49 =52

2005-10-11 17:11:40 · answer #5 · answered by Frank 7 · 0 0

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2005-10-11 17:09:38 · answer #6 · answered by *9*9 3 · 0 0

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