向量,矢量(數學)問題02

Question

如果
x =
[x1]
[x2]

a =
[a1]
[a2]

然後 kx = a

show by equating component that
x = 1/k 乘以 a

很抱歉國語不會翻問了英文的閱覽：58 還是沒答案

Answer 1

kx = k[x1 x2]^t = [kx1 kx2]^t = a = [a1 a2]^t
所以 kx1 = a1, kx2 = a2
x1 = (1/k)a1, x2 = (1/k)a2
所以 x = [x1 x2]^t = [(1/k)a1 (1/k)a2]^t = (1/k)[a1 a2]^t = (1/k)a