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x+y+z+u :10
2x-y+3z-4u : 9
3x+2y-z+5u :13
x-3y+2z-4u : -3

2007-03-22 08:58:18 · 4 respuestas · pregunta de Anonymous en Ciencias y matemáticas Otras ciencias

4 respuestas

x=2
y= 3
z= 4
u= 1

¿Qué tal?

2007-03-22 09:05:35 · answer #1 · answered by claudio 6 · 0 1

no mammes ppendejo, resuleve tu tarea solo usa matrices buey .....suerte

2007-03-22 19:56:35 · answer #2 · answered by Anonymous · 0 0

Lo mejor es resolverlo usando matrices
x y z u
1 1 1 1 10
2 -1 3 -4 9
3 2 -1 5 13
1 -3 2 -4 -3
Las filas representan ecuaciones, cada numero es el multiplicador de una variable.
1 1 1 1 10
0 3 -1 6 11_________(2) = (1)*2 - (2)
0 1 4 -2 17_________(3) = (1)*3 - (3)
0 4 -1 5 13_________(4) = (1) - (4)

1 1 1 1 10
0 3 -1 6 11
0 0 13 -12 40________(3) = (3)*3 - (2)
0 0 -1 9 5_________(4) = (2)*4 - (4)*3

1 1 1 1 10
0 3 -1 6 11
0 0 13 -12 40
0 0 0 105 105_______(4) = (3)+(4)*13

(4): 105u = 105 => u=1
(3): 13z - 12u = 40 => 13z = 40+12*1 => z= 52/13 = 4
(2): 3y -z +6u = 11 => 3y = 11+z-6u = 11+4-6 = 9 => y = 3
(1): x+y+z+u = 10 => x = 10-y-z-u = 10-3-4-1 = 2

x=2 y=3 z=4 u=1 :O)

2007-03-22 17:03:05 · answer #3 · answered by borzh62 2 · 0 0

u=1
x=2
y=3
z=4

2007-03-22 16:05:28 · answer #4 · answered by Alane23 2 · 0 0

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