i just want to know if my answer is correct. I got x^2+4x-8 divided for x-3. My ansewr is x+7+13/x-3 is it correct
2006-11-29 05:27:36 · 5 respuestas · pregunta de Karla 1 en Ciencias y matemáticas ➔ Matemáticas
It is true that (x-3)[x+7+13/(x-3)]=x²+4x-8
But that's not the correct answer. Your teacher wants a polinomial as a result and de remanent of the operation.
The correct answer is
(x²+4x-8)/(x-3) = x+7 witx remanent r(x)=15.
You can verify that (x-3)(x+7)+15=x²+4x-8
2006-11-29 05:41:31 · answer #1 · answered by Dan 3 · 0⤊ 0⤋
it no correct
x^2+4x-8:x-3 is x+7 and residue 13
comprobation
(x+7)(x-3) +13=x^2+4x-8
2006-11-29 18:54:00 · answer #2 · answered by cacara05 2 · 0⤊ 0⤋
The correct answer is: ( x + 7 ) ( x - 3 ) + 13 = x^2+4x - 8
2006-11-29 15:51:50 · answer #3 · answered by alibe 2 · 0⤊ 0⤋
The correct answer:
7 +(13 / (-3+x)) + x
your answer is correct.
2006-11-29 14:22:08 · answer #4 · answered by Fotón 5 · 0⤊ 0⤋
I'm in a place with no pencil nor paper sheets, but a nice and secure form to check your answer is to calculate the product of what you have got times x-3. At a first glance it looks correct, in the case where 13/x-3 means 13/(x-3), if you meant (13/x)-3 then your answer is incorrect.
best regards
2006-11-29 13:41:34 · answer #5 · answered by locusfree 2 · 0⤊ 0⤋