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Titration of an oxalate sample gave the following percentages: 15.55%, 15.55%, and 15.65%. Calculate the average and the standard deviation.

Can someone please help me answer this question? Please show its done.
thanks

2007-11-04 11:38:21 · 1 answers · asked by abc 1 in Science & Mathematics Chemistry

1 answers

man thas hard go

2007-11-04 11:54:13 · answer #1 · answered by randike2007 1 · 0 0

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