Please Help !!!?

Question

Question:

Can someone please tell me how each of the following changes would affect the amount of the specified substance recovered?


1. the recovery of CaCO3 was attempted by adding 3M H2SO4 instead of 3M HCl to the SiO2 / CaCO3 residue

2. the recovery of CaCO3 was attempted by adding 1M KNO3 solution instead of 1M K2CO3 solution to the filtrate, containing aqueous CaCl2


I also have to write a double displacement reaction that occurs between each of the reagents.

Thanks in advance.

Answer 1

1. CaSO4 is insoluble, and so the reaction would just clog up:

CaCO3 + H2SO4 ----> CaSO4 + CO2 + H2O

2. Aqueous CaCl2 does not react with KNO3, because all possible reactants and products are soluble.

Answer 2

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