1\x+5 = 2\2x+1 and 3\2y+2y\y-4= -11\2
I'm struggling with Least Common Denominator mostly.
2007-05-15 15:27:13 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1\(x+5) = 2\(2x+1) and
3\(2y)+2y\(y-4)= -(11\2)
2007-05-15 15:43:00 · update #1
With stuff like this, you usually wont have luck with least common denominators.
In the first equation, you are actually better off cross multiplying to get 2x+1 = 2x+10, which is inconsistant.
In the second equation, 2y(y-4) is your common denominator, soyou will have
3(y-4) + (2y)^2 = (-11)*(y(y-4))
You can work out the math to solve this.
2007-05-15 15:37:21 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
you have to be more specific is it 1/(x+5) or (1/X)+5 put parantheses in your equations in all of them.
2007-05-15 22:35:20 · answer #2 · answered by icemoon 2 · 0⤊ 0⤋