2007-04-27 11:52:05 · 5 answers · asked by cbz 1 in Science & Mathematics ➔ Chemistry
using PV = nRT, standard pressure is 1.00atm, and temperature is 273K and 7.0g CO = 7.0 x 1/28 g/m CO = .25moles
(1.00)(V) = (.25 moles CO)(.0821)(273K)
btw .0821 is something that you have to memorize: its always going to be that
2007-04-27 11:58:00 · answer #1 · answered by Anonymous · 0⤊ 0⤋
CO's molecular weight is 28 since O=16 and C=12.
Hence 7 grams is 0.25 mole.
By the ideal gas law, pV = nRT, the answer is 5.6 litres.
2007-04-27 11:59:33 · answer #2 · answered by Levent 2 · 1⤊ 0⤋
Molecular weight of CO=28(12+116).One gram molecule(mole) of CO at NTP will occupy 22.4 liters. calculate for 7 grams.22.4x7/28=5.6 liters at NTP.
2007-04-27 12:35:07 · answer #3 · answered by ssrvj 7 · 0⤊ 0⤋
Use Pv = nRT
2007-04-27 11:59:31 · answer #4 · answered by delilah 2 · 0⤊ 0⤋
you need to use PV=nRT
2007-04-28 09:29:48 · answer #5 · answered by Anonymous · 0⤊ 0⤋