Pilar kicks a soccerball such that the height, h, the ball is above the ground is a function of the distance,d, the ball has traveled down feild. h(d)=-100d^2+2/5d. Both d and h are measured in meters. How far downfeild will the ball have traveled when it hits the ground? What is the greatest height that the ball reaches?
can anyone help me? and show me the work thanks
2007-04-01 16:42:07 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
h(d) = -100d^2 + 2/5 d.
When the ball hits the ground, h(d) = 0. So
-100 d^2 + 2/5 d = 0
<=> d (-100d + 2/5) = 0
<=> d = 0 or d = (2/5)/100 = 0.004 m = 4 mm.
The maximum height is at d = 0.002 m and is -100(0.002)^2 + 2/5 (0.002) = 0.0004 m = 0.4 mm.
(Check to see if the question has been typed in correctly... if it was -d^2/100 + 2/5 d it would make more sense and wind up as 40m distance and 4m height.)
2007-04-01 16:55:15 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋