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I have two chem problems that i cant solve help please

My base is Al(ClO3)3 aluminum chlorate

I have to solve the following freezing point depression and boiling point elevation probelm.

1. Using an oppropriate solvent (and the correct freezing point depression constant for the solvent), determine how many grams of solute are required to lower the freezing point of 2.00kg of the solvent by 5.00 degrees Celcius. (remeber that for ionic solutes you must multipy the effect by the number of ions that dissociate in solution).

2. Using an appropriate solvent (and the correct boiling point elevation constant for that solvent), determin how many grams of solute are required to raise the boiling point of 2.00kg of the solvent by 5.00 degrees Celcius. (remeber that for ionic solutes you must multiply the effect by the number of ions that dissociate in solution).

PLEASE HELP ME!!

2007-03-28 09:51:56 · 2 answers · asked by mitchel l 2 in Science & Mathematics Chemistry

2 answers

I don't know, but have you tried checking wikipedia?

2007-04-01 07:46:44 · answer #1 · answered by David W 4 · 0 0

25. pH = -Log[H+] [H+] = 10; Log10 = one million; -Log10 = -one million, a meaningless variety, by way of fact pH is used in ordinary terms for extremely dilute suggestions. 26. Kw = [H+][OH-] = 10^-14 [H+](10) = 10^-14 [H+] = 10^-15 pH = 15 additionally a meaningless variety. as quickly as you get to 10M acid or 10M base, the liquid no longer resembles water. In those suggestions, pH = -Log(a), the place a is the interest of the [H+]. to be attentive to that,you ought to multiply [H+] by the interest coefficient. 27. [H+] = 0.01; Log(0.01) = -2; pH = 2 28. You copied the undertaking incorrect 29. pH = 3.7; so Log[H+] = -3.7 = -4 + 3; then [H+] = 2 x 10^-4 30. i assume you advise that [H+] = 6.8 x 10^-10 (6.8x10^-10)[OH] = 10^-14 [OH-] = one million.5 x 10^-5; pOH = 5; pH = 9 31. 50.0C - 20.0C = 30degC difference. 15.5gH2O x 30degC x 1cal/deg-g = 465 cal 32. it rather is impossible for water to condense from steam to water at 1000C. That temperature is plenty above the intense temperature of water, above which water won't be able to be condensed to liquid no count how great the stress. i believe which you extremely want to be attentive to the flexibility released while steam is cooled from 1000C to100C and then condensed to water on the comparable temperature. For that, you may ought to have the warmth potential of steam and the latent warmth of vaporization of water.

2017-01-05 08:38:17 · answer #2 · answered by ? 3 · 0 0

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