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1- vinegar
chemical name: acetic acid
formula:CH3COOH
2-Baking soda:
chemical name:Sodium be Carbonate
formula:NaHCO3

2007-03-17 09:33:07 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

The reaction between baking soda and vinegar is an acid-base reaction followed by the dissolution of a gas.

HOAc + NaHCO3 --> NaOAc + H2CO3

H2CO3 --> H2O + CO2(gas)

Here, "Ac" is an abreviation for acetate, CH3CO2.

2007-03-17 09:39:36 · answer #1 · answered by BP 7 · 0 0

Baking soda, a pure chemical called sodium bicarbonate, has the chemical formula:

NaHCO3

When dissolved in water baking soda separates into sodium (Na+) and bicarbonate ions (HCO3- ):

NaHCO3 ---> Na+(aq) + HCO3-(aq)


Vinegar, a weak (5%) solution of acetic acid in water, partially dissociates into hydrogen ( H+) and acetate ions (CH3COO-):

CH3COOH <--> H+(aq) + CH3COO-(aq)

The reaction between baking soda and vinegar is actually two reactions, an acid base reaction followed by a decomposition reaction.

When the two ingredients are mixed, hydrogen ions ( H+) from the vinegar react with the bicarbonate ions (HCO3- ) from the baking soda to form a new chemical called carbonic acid (H2CO3).

H+ + HCO3- ---> H2CO3

The carbonic acid thus formed then immediately decomposes into carbon dioxide gas (CO2)and water (H2O).

H2CO3 ---> H2O + CO2

It's this carbon dioxide gas that you see bubbling and foaming as soon as you mix baking soda and vinegar together.

2007-03-18 09:26:11 · answer #2 · answered by wayne c 3 · 0 0

there is not any enormous difference in the "carbon dioxide" CO2 is CO2. the enormous difference i imagine you're relating is is the most concentration of CO2 in the ballon. relying on the gasoline the balloon is in is what makes it "glide" more advantageous powerful. the balloon with the CO2 will glide more advantageous powerful.

2016-11-26 19:17:12 · answer #3 · answered by ximenez 4 · 0 0

CH3CO2H + HCO3- ----> CH3CO2- + H2CO3
H2CO3 ---> H2O + CO2

2007-03-17 09:37:36 · answer #4 · answered by TheOnlyBeldin 7 · 0 0

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