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Calculate the pH of a mixture containing equal volumes of?

0.540 M NH4Cl ( use Ka = 5.60 x 10 -10 ) and 0.540 M NH3.

2007-03-16 15:29:39 · 1 answers · asked by Gemini 2 in Science & Mathematics ➔ Chemistry

1 answers

pOH = pKb + log ( salt / base )
= - log ( 10^ -14 / 5.6 x 10^-10) + log ( 0.540 /0.540)
= 4.75

pH = 14 - 4.75 = 9.25

2007-03-16 15:58:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋

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