English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1. 1.0g NaOH and 50mL H2O
NaOH(s) + H2O(l) --> Na+(aq) + OH-(aq) + H2O(l)

2.1.0g NaOH and 50mL HCl of 1.0M
NaOH(s) + HCl(aq) --> NaCl(aq) + H2O(l)

3. 25mL NaOH and 25mL HCl
NaOH(aq) + HCl(aq) --> NaCl(aq) + H2O(l)

so basically, 1. solid base and water, 2.solid base and acid, 3. base solution in acid
(do bubbles get formed for everyone of them, which one has more bubbles or any observation)

2007-03-16 14:41:54 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Heat would be given off in all 3 reactions. If you look at the products you have shown in the reactions, you'll notice that there are no gases given as products, therefore no bubbles.

Reaction #2 would definitely be the most reactive. After all you're adding a very strong base to a very strong acid.
I'd stand back a little bit for that one, it could splatter.

It's difficult to say for sure about #3 without the concentrations, but I would say it's still less reactive than #2 because the NaOH is already dissolved in #3.


also.....

2007-03-16 14:48:48 · answer #1 · answered by BP 7 · 0 1

1. The solid NaOH dissolves to form a water-white solution. No bubbles, but the solution may get just the slightest bit warmer.

2. The same, except the solution may get a tad warmer than in 1.

3. No noticeable warming, no bubbles.

2007-03-16 14:52:40 · answer #2 · answered by steve_geo1 7 · 0 2

fedest.com, questions and answers