Why is NaCl soluble in water, yet sulfur (S8) is not?

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Why is NaCl soluble in water, yet sulfur (S8) is not?

2007-03-15 17:17:41 · 3 answers · asked by amigo 2 in Science & Mathematics ➔ Chemistry

3 answers

Water is bipolar, the bond between NaCl is weak, and thus the bipolar water molecule easily breaks that bond.

Whereas the S8 bond is too strong to be broken by the bipolar properties of water.

2007-03-15 17:30:28 · answer #1 · answered by James M 6 · 0⤊ 0⤋

NaCl is a polar salt which is ionic and this makes it soluble because water is a polar solvent but sulfur (S8) is not soluble because the sulfur molecule is formed from the complex combination of sulfur atoms which forms covalent bonds with one another to form a non polar molecule.

2007-03-16 17:00:22 · answer #2 · answered by Samuel_007 2 · 0⤊ 0⤋

because NaCl (sodium flouride) is salt and salt is soluble in water

2007-03-16 00:24:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋