What is the formula for butane (C4H10) combusted in air?
2007-03-15 15:47:44 · 5 answers · asked by Ham Wallet 1 in Science & Mathematics ➔ Chemistry
Partially or totally combusted??
2(C4H10) + 13O2 --> 8CO2 + 10H2O
2007-03-15 15:52:15 · answer #1 · answered by IIDX Chem 3 · 0⤊ 0⤋
The unbalanced combustion equation is
C4H10 + O2 -> CO2 + H2O
Note, that to balance compounds
moles of CO2= 4 moles of butane
moles of H20 = 5 moles of butane
Pick one mole of butane as a trial start
C4H10 + ?O2 -> 4CO2 + 5 H2O
We need 13 "atoms" of O, but since oxygen comes as O2, we have 6-1/2 moles. To go to a whole number, multiply by 2
2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O
2007-03-15 15:55:41 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
C4H10 + 6.5 O2 ==> 4CO2 + 5H2O ...
or
2(C4H10) + 13O2 ==> 8CO2 + 10H2O
2007-03-15 15:51:20 · answer #3 · answered by Brewmaster 4 · 0⤊ 0⤋
C4H10 + (6.5)O2 = 4CO2 + 5H2O (Complete combustion)
C4H10 + 6O2 = 3CO2 + 5H2O + CO (Incomplete combustion)
2007-03-15 17:15:39 · answer #4 · answered by Norrie 7 · 0⤊ 0⤋
2C4H10+13O2 = 8CO2 + 10H2O
2007-03-15 15:53:40 · answer #5 · answered by Anonymous · 0⤊ 0⤋