1.625g of pure acetylsalicylic acid in distilled water and titrated the resulting solution to the equivalence-

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1.625g of pure acetylsalicylic acid in distilled water and titrated the resulting solution to the equivalence-

point using 88.43 ml of .102 M NaOH(aq). Assumming that the acid has only 1 ionizable hydrogen, calculate the molar mass of the acid.

2007-03-15 15:03:27 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

1 answers

Determine the MOLES of NaOH used
0.102 mole/liter x 0.08843 L = 0.009 moles appx.
That the number of moles in 1.625 g of the acid, and its weight is 1.625/0.009

2007-03-15 15:16:14 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋