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3 answers

At standard temperature and pressure, one mole of gas is to occupy 22.4 l.
So, you should have 1/22.4 mole, or 30/22.4 g, which works out to 1.339 g.

2007-03-14 15:14:20 · answer #1 · answered by Vincent G 7 · 1 0

Your teacher will want to see the working out

Using the Idea gas law.

PV = nRT

etc n = 22.5 moles per L

so the weight of one L of ethane is
22.4 moles x 30 g/mol = 67.2 grams

2007-03-14 22:19:28 · answer #2 · answered by Mr Hex Vision 7 · 0 1

ethane is C2H6

2007-03-14 22:17:47 · answer #3 · answered by irishrunner1 5 · 0 0

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