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C2F4
NH2CH2COOH
C5H2
CH2CHCl

2007-03-14 12:06:01 · 3 answers · asked by William R 1 in Science & Mathematics Chemistry

3 answers

I think your third example should read C5H12. If that is so, then it is saturated, and cannot be a monomer. Glycine can form a polymer, as can tetrafluoroethene and chloroethene.

2007-03-14 12:16:39 · answer #1 · answered by Gervald F 7 · 1 0

NH2CH2COOH

i did it by elimination, the others must be monomers because they are all simple, this one looks a bit complex and looks like it could be arranged in more than one way

2007-03-14 19:09:59 · answer #2 · answered by alex 2 · 0 2

the second one is an ester, which is a double bonded O and a single bonded O on a carbon.

2007-03-14 19:24:20 · answer #3 · answered by adamstivala 2 · 0 0

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