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3 answers

Work out 10-11.5 for [H+] and 10-2.5 for [OH-]

2007-03-14 07:16:38 · answer #1 · answered by Gervald F 7 · 0 0

pH = -log [H+] , ==> [H+] = 10^-pH = 10^-11.50

Kw = 10^-14 = [H+][OH-] ==> [OH-] = 10^-14/[H+]

2007-03-14 07:22:49 · answer #2 · answered by Calvin S 1 · 0 0

[H+] = 10^-11.5
[OH-] = 10^-2.5

2007-03-14 07:17:15 · answer #3 · answered by Michael Dino C 4 · 0 0

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