through the ideal gas law.
800 torr-->1 atm
25 C--> 298 K
R= .0821
PM=dRT
2007-03-13 18:18:54 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
.0821 L(atm)/mol(k)
the mole doesnt get canceled out if M is in grams..
2007-03-13 18:24:15 · update #1
Density = mass/volume = P*MM/RT
800 torr is not 1 atm, it is 1.053 atm.
Density = 1.053*17/(0.08206*298) = 0.732 g/L
As for M being in grams, your equation is wrong. Density is mass/volume. To get that from the Ideal Gas Law, you have to change n to mass/molar mass, and solving you get that density is equal to pressure times molar mass divided by the Ideal Gas Constant and temperature. It's supposed to be MM, not M, which is in grams/mole.
2007-03-13 18:24:54 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 1⤋
7
2007-03-14 01:21:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The density at STP for NH3 is 14+3 grams per 22.4 liters, or 0.7589 grams per liter. The density under the conditions given is 0.7589 x 800/760 x 273/298. Note that I used the standard Avogadro volume rather than the gas constant; the result is the same.
2007-03-14 01:25:25 · answer #3 · answered by Anonymous · 0⤊ 1⤋