MnO4(supscript) -(Superscript) + 5Fe 2+ + 8H+ yields Mn2+ + 5Fe 3+ + 4H2O...?

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MnO4(supscript) -(Superscript) + 5Fe 2+ + 8H+ yields Mn2+ + 5Fe 3+ + 4H2O...?

How do I find out what the Oxidized species is and what the Reduced Species is?

2007-03-13 15:41:00 · 2 answers · asked by ma.roddy 1 in Science & Mathematics ➔ Chemistry

2 answers

MnO4- o.n.(Mn)= +7
Mn2+ o.n.=+2
so Mn goes from +7 to+2 : reduced specie

Fe2+ o.n. = +2
Fe3+ o.n. =+3
so Fe goes from +2 to +3 : oxidized specie

2007-03-14 06:51:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Use the valence rule method. oxygen is alway -2, H is alway +1 etc. If the valance is lowered, it is the reduced species. If the valance is increased, it is the oxidixed species. In this case, Mn drops form +7 to +2, while iron goes from +2 to +3.

2007-03-13 22:50:44 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋