a)SO2, b) SO3, c) N2O3, d) N2O5
You take the molar mass of each of the compounds, i.e. S is 32.07, N is 14.00, O is 16.00.
You can automatically eliminate SO2 and N2O3 since its percent O is definitely is lower than SO3 and N2O5 respectfully.
Now..
b) SO3 Molar mass 32 + (16 x 3) = 80.
(16 x 3)/80 = 60%
d) N2O5 Molar mass 2 x 14 + (16 x 5) = 108.
(16 x 5)/108= 74%
Answer is d
2007-03-13 13:55:05
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answer #1
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answered by bolusoo 2
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As PERCENTAGES go, I would have thought
SO3 - because 75% is oxygen, wheras with N2O5, then surely, the oxygen (although 5) is actually only 71%
1:3 is higher than 2:5
Mark
2007-03-13 16:08:53
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answer #2
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answered by Mark T 6
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Make a little list
Compound Mol Wt WtO
SO2 64 32 half O
SO3 80 48 3/5 th O
N2O3 72 48 about 2/3 O
N2O5 108 80 looks like the one
2007-03-13 13:49:15
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answer #3
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answered by cattbarf 7
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d beacuse it says "0" wich stands for oxygen and "5" wich means 5 parts of oxygen. theres 5 parts of oxygen in answer choice d. 2 in a. 3 and b. 3 in c.
2007-03-13 13:47:55
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answer #4
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answered by kieran 2
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N2O5 ....
That compound has 5 oxygen's.
(O means oxygen and the number 5 is how many oxygen's it has)
2007-03-13 13:47:30
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answer #5
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answered by Steph 4
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N2O5
2 parts nitrogen and 5 parts oxygen
2007-03-13 13:46:51
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answer #6
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answered by Anonymous
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N2O5
because it have 5 parts oxygen .
2007-03-13 14:44:48
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answer #7
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answered by gotarz 1
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SO3 - just guessing, i fell asleep in organic chemistry
2007-03-13 13:47:23
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answer #8
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answered by ropman1 4
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divide the molecular weight of the amount of oxygen by the molecular weight of the entire compound, and you have your percentage.
2007-03-13 13:47:37
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answer #9
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answered by pentech_99 2
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