NaF or BaF2 (2 is subscript after F) I know the BaF2 would form the stronger bond, but why?
I am doing ionic and covalent bonding and Lewis dot structure and stuff.
Thanks if you can help.
2007-03-05 14:16:49 · 2 answers · asked by Boo Radley 4 in Science & Mathematics ➔ Chemistry
BaF2 would form the stronger bond due to the fact that Ba has a +2 charge while Na only has a +1 charge. Because it is more positive, it will have a greater ionic attraction to the F molecule.
2007-03-05 14:26:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Na is a smaller atom, the distance between the Na and F atoms would be smaller, and so according to Coulomb's Law, less distance = more force. But I don't think it compensates fully for the higher charge.
The BaF2 has the Ba 2+ ion in it. The NaF has Na+ ion in it. The barium ion has a greater charge, and therefore greater force exerted on the fluorine atoms, because both compounds are ionic.
2007-03-05 14:30:12 · answer #2 · answered by doctorevil64 4 · 0⤊ 0⤋