What is the molarity of an aqueous solution containing 22.5g of sucrose (C12H22O11) IN 35 ml of solution?

Question

a. 0.0657
b. 0.00185
c. 1.85
d. 3.52
e. 0.104

Answer 1

Molecolar weight of sucrose is 342.3 g/mol
V=35 ml=0.035 l
22.5 g>>0.0657 mole
in fact 1mole : 342.3 g = x mole : 22.5 g
Molarity= moles/liter= 0.0657/0.035=1.87M that is similar answer c