how do i find total energy after 0.35 seconds of jumping off a 27m cliff w/ a mass of 80kg?

2007-03-05 10:50:12 · 2 answers · asked by damigurl05 1 in Science & Mathematics ➔ Physics

energy is conserved, so the energy after .35 seconds is the same as the energy at the top. just do mgh.
(80)(27)(9.8)=21168j

2007-03-05 10:56:56 · answer #1 · answered by climberguy12 7 · 0⤊ 0⤋

E=Mc2

2007-03-05 18:58:38 · answer #2 · answered by Princess Amber 2 · 0⤊ 0⤋

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