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In the picture, (Click on link for image)... what is the acceleration of the crate if the applied force is 330 N and the coefficient of kinetic friction is 0.45.

Angle of the applied force is 21 degrees with respect to the negative x-axis... the crate weighs 32 kg.

LINK FOR IMAGE: http://img.photobucket.com/albums/v156/PNHTran88/phys.jpg

Thanks!!

2007-03-04 14:30:09 · 1 answers · asked by 123haha 1 in Science & Mathematics Physics

1 answers

free body diagram

x-direction

Fcos(21)-uN=ma

y direction
-Fsin(21)-mg+N=0

N=Fsin(21)+mg=330sin(21)+32*9.8=431.9 N

330cos(21)-.45(431.9)=32a

a=113.7/32=3.6 m/s^2

2007-03-04 14:41:41 · answer #1 · answered by Rob M 4 · 0 0

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