English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

HCl acidifies [ Zn(NH3)4]2+ and Na2Co3 is added to this. The precipitate is ZnCo3
and....
HNO3 acidifies Pb(OH)2 and Na2CO3 is added to this. This precipitates PbCO3

2007-03-02 09:30:20 · 3 answers · asked by RT 2 in Science & Mathematics Chemistry

3 answers

Tetrammine zinc (II) complex, [Zn(NH3)4]^+2, does react with HCl:

[ Zn(NH3)4]2+ (aq) + 4 HCl (aq) --> Zn+2 (aq) + 4 NH4Cl (aq)

Zn+2 (aq) + Na2CO3 (aq) --> ZnCO3 (s) + 2 Na+ (aq)

The second takes 2 steps:
2 HNO3 (aq) + Pb(OH)2 (s) ---> Pb(NO3)2 (aq) + 2 H2O (l)

Pb(NO3)2 (aq) + Na2CO3 (aq) ---> PbCO3 (s) +2 NaNO3 (aq)

Or overall:
2 HNO3 (aq) + Pb(OH)2 (s) + Na2CO3 (aq) ---> PbCO3 (s) + 2 NaNO3 (aq) + 2 H2O (l)

2007-03-06 06:35:38 · answer #1 · answered by Richard 7 · 10 0

NH3 is ammonia and does not have a charge
NH4+ is ammonium ion, it does not combine with Zn, both positively charge
Please write carbonate as CO3-2, Co is cobalt

2HNO3 +Pb(OH)2 +Na2CO3 --->PbCO3(s) +2NaNO3 +2H2O

2007-03-02 17:42:03 · answer #2 · answered by science teacher 7 · 0 0

go to google and search equation balancer

i hope this really helps you in the future, as it did for me!!!

2007-03-02 17:34:26 · answer #3 · answered by angel3mja 2 · 0 0

fedest.com, questions and answers