2007-03-02 04:01:09 · 4 answers · asked by frickenawesomekoreanandyouknowit 2 in Science & Mathematics ➔ Chemistry
base on the below balance equation:
2CO(g)+O2(g)--> 2CO2(g)
20 L of carbon dioxide will weigh.
28gCO(1molCO/28gCO)
(2molCO2/2molCO)
(44gCO2/imolCO2)= 44gCO2
2007-03-02 07:17:39 · answer #1 · answered by bige1236 4 · 0⤊ 0⤋
Assuming all follow the same gas law, are all the same temperature, and pressure then you will calculate based on weight ratios.
MW_carbon dioxide = 44
MW_oxygen = 32
MW_carbon monoxide = 28
w_oxygen = 32
w_carbon monoxide = 28
w_oxygen/MW_oxygen = w_carbon monoxide/MW_carbon monoxide = w_carbon dioxide/MW_carbon dioxide
w_carbon dioxide = MW_carbon dioxide*w_oxygen/MW_oxygen = MW_carbon dioxide*w_carbon monoxide/MW_carbon monoxide
w_carbon dioxide = 44*32/32 = 44*28/28
w_carbon dioxide = 44 = 44
Therefore, from both data points we gather that the weight of 20 L of carbon dioxide is 44g.
2007-03-02 13:01:18 · answer #2 · answered by Tim 4 · 0⤊ 0⤋
i'm guessing they want 44g, since oxygen is diatomic 28 + 1/2 (32). however, this is dependent of pressure and temperature.
2007-03-02 12:07:53 · answer #3 · answered by Troy 6 · 1⤊ 0⤋
60g
2007-03-02 12:04:05 · answer #4 · answered by Anonymous · 0⤊ 1⤋