of C12H22O11 in amu.
What I did was multiply the number of each element x it's atomic mass: 6(12.0 amu) + 22(1.0 amu) + 11(16.0 amu) = 342.0 amu but when I put this answer in, the answer key tells me it's wrong! What am I doing wrong??
2007-02-06 07:34:32 · 3 answers · asked by DJ 1 in Science & Mathematics ➔ Chemistry
*EDIT*: I'm sorry, I meant to put 12(12.0 amu) for Carbon not 6(12.0 amu). THAT'S how I got 342.0 amu but it still says i'm wrong.
2007-02-06 08:39:55 · update #1
do you have 12 carbon's? from your question/answer it looks like you need to multiply 12 by 12 to account for your 12 carbons
2007-02-06 07:42:52 · answer #1 · answered by mizzouswm 5 · 1⤊ 0⤋
mizzouswm has detected the error, and you should award her/him the 10 points.
C12 12 x 12 = 144
H22 22 x 1 = 22
O11 11 x 16 = 176
____
342
2007-02-06 07:52:36 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
well, the way atomic weights work is that they are an average of the possible isotopes in their existing forms.
About 1.3 % of carbon atoms are C^13 (they have an extra neutron), so they take a weighted average and give carbon a molecular weight of 12.011 grams / mole, or 12.011 AMU/molecule
So its (6x12.011) + (22x1.008) + (11 x 15.999) = 270.231, plus your math is wrong, your math should equal 270. Check your calculator
2007-02-06 07:42:54 · answer #3 · answered by Steve D 2 · 0⤊ 0⤋