add them up, divide by 6 - that's mean.
subtract mean from every number, square each result, add them up, divide by 5, take square root.
6 is how many numbers you have. 5=6-1; you can divide by 6 in the last step too, but it is less precise.
Also, a statistician will say that 6 observations is way too few to do the kind of statistical analysis that uses standard deviation.
2007-01-31 15:33:25
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answer #1
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answered by Anonymous
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Um, what grew to become into the advise? the standard deviation by using itself would not quite advise something. yet, this sounds very severe, such as you in line with threat have undesirable records (i.e., you made a length blunders). you may tell from observing your numbers: are they in each and every single place? Or are you handling enormous (nutrition) energy or little (technological information) energy? (Stupidly, a million nutrition calorie = one thousand technological information energy) in the event that they're the small energy, that's probable completely superb. the standard deviation tells you techniques a lot your numbers bounce around.
2016-11-23 19:14:33
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answer #2
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answered by hamman 4
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Find the average of the numbers, call it m. Subtract each datum (x1, x2, ...) from m, and square what you get. (m - x1)², (m - x2)², and so on. Find the average of these squares, Σ(m - xi)²/6. Finally, take the square root. That's the std dev.
2007-01-31 15:43:03
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answer #3
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answered by Philo 7
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ick, I don't think there is a way? Does using your calculator instead of excel count as work, that's how we did it.
2007-01-31 15:33:27
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answer #4
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answered by Kipper to the CUP! 6
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first of all, you have to determine the mean. then for each data we can formulate it as
add (x-y)^2 from x1 to xN
then divide above line's result by N
then sqrt
x=data
y=mean
N=data amount
2007-01-31 15:38:08
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answer #5
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answered by emerzagor 2
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