at 25 degrees the PH of a .45 mol/l butanoic acid C3H7COOH solution is 2.90. calculate the Ka for the acid?

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at 25 degrees the PH of a .45 mol/l butanoic acid C3H7COOH solution is 2.90. calculate the Ka for the acid?

2007-01-22 10:52:02 · 2 answers · asked by gst 1 in Science & Mathematics ➔ Chemistry

2 answers

Start with the equation from your book for the Ka of any weak acid. Next, convert the pH into a hydronium ion concentration. Reconize that the concentration of the butanoate ion will equal the hydronium ion (proton) concentration, and that virtually all of the butanoic acid is still in the un-ionized form.

Plug these values into the equation for Ka, and calculate it.

2007-01-22 10:58:07 · answer #1 · answered by hcbiochem 7 · 1⤊ 0⤋

october?

2007-01-22 18:55:33 · answer #2 · answered by Baked n Blended 5 · 0⤊ 1⤋