When 13.98 mL of HCL of unknown concentration (but less than that of a the base) are reacted with 15ml of 3.07 M NaOH, 2.08 kJ of heat are released. From these experimental data, calculate the molarity of the HCL solution.
2007-01-22 10:22:10 · 2 answers · asked by nitral2344 1 in Science & Mathematics ➔ Chemistry
I still don't understand how to do it despite his answer.
2007-01-22 11:41:06 · update #1
You're going to need to find the heat of reaction of HCl and NaOH. That value should be expressed in terms of kJ/mol, and will be the energy released when 1 mol of HCl reacts with 1 mol of NaOH. With that standard value and the amount of heat released in the problem, you can calculate the number of moles of HCl that were used in the reaction. Divide that by the volume of HCl (expressed in L) and you've got the answer.
2007-01-22 10:31:15 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
looks like hcbiochem just answered your question!
I was gonna say the same thing but no use!
2007-01-22 18:36:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋