How would I use stoichiometry to determine how much NA2CO3 I would need to make a full reaction.?

Question

here is the equation: NA2CO3 + CACL2.H20>CACO3 + 2NACL + 2H20. I have already weighed out one gram of CACL2.H20

Answer 1

The methodology for this is as follows:
- Calculate the number of moles of CaCl2.H2O.
- Calculate the required number of moles of Na2CO3 to completely react with this (this is the stoichiometry bit). From the equation 1 mol of Na2CO3 reacts with 1 mol of CaCl2.H2O, so this will be the same as the first figure.
- Then calculate the formula mass of Na2CO3 and thence the mass of Na2CO3 corresponding to the required number of moles.

Answer 2

determine the number of moles that you have of the calcium chloride dihydrate, and because it is in a 1 to 1 mole ratio with the sodium carbonate, determine the mass of that number of moles of the sodium carbonate.