Why is the configuration of 8 electrons in the valence shell of an electron structurally stable?

Question

Give clear reason why an atom with 8 electrons in the valence shell is in the minimum state of energy. And what is the basis of Lewis and Kosell's Octet Rule- Is it merely observation of valence shell configurations of several atoms or there is some strong reasoning behind it and if so what is the reason.

Answer 1

s - orbitals can take at most 2 electrons (Pauli's principle) and p - orbitals can take at most 6 electrons. A closed shell usually ends up with filled s and p orbitals. 2 + 6 = 8. The d - elements and f - elements have d - and(or) f - orbitals, so they may have different valencies.

Answer 2

In an atom the electrons are prepared in shells and as you're saying 8 electrons in valence shell is maximum sturdy is a moderate incorrect theory.actual the no of electrons should be paired (as in case of He.With in effortless words 2 electrons it truly is a sturdy one)it really is asserted that 8 electrons are maximum sturdy because we continuously communicate of representative elements which require 8 electrons to be maximum sturdy.accordingly better than 8 yet paired and concerning the equation no.of electrons in valence shell=2n^2 the position n is the no.of valence shell.So. 18 ,36 are extra stabler than 8 electrons interior the valence shell.

Answer 3

the state of ur knowledge is a little low as compared to ur question (i said knowledge an not intelligence).
try and find some info about the quantum mechanical structure of atom. which will include sub-shells like s,p,d,f,etc. based on this, follow the periodicity. there u will find the answer.

Answer 4

the inert gases helium, neon,argon,krypton,xenon etc are stable and have stable configuration based on that only the octet rule is based.

Answer 5

2s2,2p6