Please help me with this one, I am really stumped.
2007-01-14 17:21:17 · 6 answers · asked by Random G 3 in Science & Mathematics ➔ Chemistry
The actual yield is 1.15 cm
2007-01-14 17:45:26 · update #1
It should be PbI2
0.001 moles
2007-01-14 17:28:24 · answer #1 · answered by andru 2 · 0⤊ 0⤋
i'm completely lost by applying the thought of measuring yield in centimeters -- that's mindless. interior the reaction, the product is PbI2; the limiting reagent is NaI, and a couple of moles of that are required consistent with mole of product, so the quantity of lead iodide could be 0.0015 moles.
2016-12-12 11:41:12 · answer #2 · answered by Anonymous · 0⤊ 0⤋
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2016-05-16 11:24:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Equation = Pb(NO3)2 + 2 NaI ----> Na2(NO3) + PbI2
Solution= So lost...cause you didnt give us hte actual yeild
2007-01-14 17:42:34 · answer #4 · answered by -Eugenious- 3 · 0⤊ 0⤋
well, in theory, I don't know what you are asking, and what is more important, I don't care.
2007-01-14 17:29:01 · answer #5 · answered by k r i s 3 · 0⤊ 0⤋
look at the question you had below...
2007-01-14 17:26:43 · answer #6 · answered by car of boat 4 · 0⤊ 0⤋