2006-12-20 23:03:42 · 8 answers · asked by Dreams 1 in Sports ➔ Wrestling
Great entertainer for sure, but great wrestler? I doubt that.
WWE is a load of bull in any case.
2006-12-20 23:23:52 · answer #1 · answered by Big Ben 3 · 0⤊ 2⤋
The Undertaker is probably WWE's greatest entertainer, wrestler, and asset. He packs arenas, he has battled his way through opponents for 16 whole years, and he still has plenty of fight left in him. Old? He's somewhere in his mid-40's, but anybody who says Undertaker is old just doesnt know how to appreciate what the Deadman has done. I doubt anyone could beat him fairly. He's an expert striker, has 'educated' arms,and has an array of moves. Here, my friend, is a superstar that came, saw, and conquered...and there will never be another likewise in history ever again.
2006-12-21 09:32:13 · answer #2 · answered by Rockafella 2 · 3⤊ 0⤋
Brock Lesnar beat him a few years ago after he knocked him out with the F-5.
2006-12-25 01:39:25 · answer #3 · answered by KISS Fan 7 · 0⤊ 0⤋
.........I often wonder does this section know that wrestling is planned? Of course someone can beat him!
Edit: Ok to the guy who just said Taker is the best professional wrestler shouldn't watch wrestling ever again. It's obvious no one in this section knows what real wrestling is. What you are all watching is Sports Entertainment AKA WWE
2006-12-21 09:49:00 · answer #4 · answered by GenerationNext 3 · 0⤊ 2⤋
there r loads of wrestler that can defeat the undertaker
2006-12-25 02:23:56 · answer #5 · answered by curious 2 · 0⤊ 1⤋
No one can beat the phenom especially when he faces someone at Wrestlemania.
2006-12-21 11:04:07 · answer #6 · answered by MAF1113 6 · 2⤊ 0⤋
YES ! HE IS A WRESTLING GOD!!!!
AND NO, NO ONE CAN BEAT HIM!!!!(remember,YOKOZUNA needed help and all of the wrestlers aided him."TAKER" STILL WAS'NT "BEAT")!AS IT SHOULD BE!!!
2006-12-22 00:21:34 · answer #7 · answered by Anonymous · 0⤊ 0⤋
i don't think so, Taker is the best professional wrestler.
2006-12-21 09:49:59 · answer #8 · answered by Ninja Rocker 2 · 3⤊ 0⤋