A skier has just begun schussing (skiing downhill without turning) down a 30 degree slope. The coefficient of sliding friction is .20. What is her acceleration rate?
2006-12-13 06:35:06 · 4 answers · asked by The Answer 1 in Science & Mathematics ➔ Physics
Downward force (F) being counteracted by the force of friction (f)
F=mgcos(30)- u mgsin(30)
a=F/m
a=g(cos (30) - u sin(30))= 9.81(.866 - .2 x .5)=
a=7.51m/sec^2
2006-12-13 06:49:50 · answer #1 · answered by Edward 7 · 0⤊ 1⤋
The force that causes her to slide down the slope is gravity. Since she's on a slope, it's not simply mg. Draw a free body diagram. There is also friction which resists and is in the opposite direction. Therefore, use:
ma = mg(sin30 - 0.20cos30)
As you can see, m gets cancelled and acceleration is 3.20 m/s^2. I used 9.8 m/s^2 for the acceleration of gravity. I hope that this helps.
2006-12-13 14:53:06 · answer #2 · answered by Philippe 3 · 0⤊ 1⤋
ma = sin(30)w-0.2cos(30)w
ma = 0.32679mg
a = 3.20259 m/(s^2)
2006-12-13 14:43:32 · answer #3 · answered by bermudask8er7 4 · 0⤊ 0⤋
you need more info. like the weight of the guy
2006-12-13 14:58:02 · answer #4 · answered by Dude 9969 1 · 0⤊ 1⤋