anyone know how to calculate the PH of 0.10 M lactic acid if its Ka = 1.37*10^-4 ?

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anyone know how to calculate the PH of 0.10 M lactic acid if its Ka = 1.37*10^-4 ?

2006-11-28 17:13:56 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

3 answers

Set up ur ICE chart

(HF) + (H2O) ------> (H3O+) + (F-)
.1 ______________+x _______ +x
.1_______________ x _______ x

x^2/.1 = 1.37*10^-4

solve for X

X gives u concentration of [h3o+]
then use
-log[H3O+] for PH

2006-11-28 17:52:42 · answer #1 · answered by ajramos_03 2 · 0⤊ 0⤋

Concentration of H+ ions is root (molarity x Ka).

Then take the negative logarithm of your H+ ion concentration.

2006-11-29 02:41:54 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋

yeah that's easy. just take the pH and multipliy

2006-11-29 01:14:58 · answer #3 · answered by private0909 1 · 0⤊ 0⤋